HDU - 5996 树上博弈 BestCoder Round #90

就是阶梯NIM博弈，那么看层数是不是奇数的异或就行了；

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<bitset>
#include<ctime>
#include<deque>
#include<stack>
#include<functional>
#include<sstream>
//#include<cctype>
//#pragma GCC optimize(2)
using namespace std;
#define maxn 400005
#define inf 0x7fffffff
//#define INF 1e18
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
#define rdult(x) scanf("%lu",&x)
#define rdlf(x) scanf("%lf",&x)
#define rdstr(x) scanf("%s",x)
typedef long long  ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const long long int mod = 1e9;
#define Mod 1000000000
#define sq(x) (x)*(x)
#define eps 1e-11
typedef pair<int, int> pii;
#define pi acos(-1.0)
//const int N = 1005;
#define REP(i,n) for(int i=0;i<(n);i++)
typedef pair<int, int> pii;

inline int rd() {
	int x = 0;
	char c = getchar();
	bool f = false;
	while (!isdigit(c)) {
		if (c == '-') f = true;
		c = getchar();
	}
	while (isdigit(c)) {
		x = (x << 1) + (x << 3) + (c ^ 48);
		c = getchar();
	}
	return f ? -x : x;
}


ll gcd(ll a, ll b) {
	return b == 0 ? a : gcd(b, a%b);
}
int sqr(int x) { return x * x; }



/*ll ans;
ll exgcd(ll a, ll b, ll &x, ll &y) {
	if (!b) {
		x = 1; y = 0; return a;
	}
	ans = exgcd(b, a%b, x, y);
	ll t = x; x = y; y = t - a / b * y;
	return ans;
}
*/
int T;
vector<int>vc[maxn];
int ans;
int a[maxn];
void dfs(int u,int fa,int dep){
	for(int i=0;i<vc[u].size();i++){
		int v=vc[u][i];
		if((dep+1)%2)ans^=a[v];
		dfs(v,u,dep+1);
	}
}
int main() {
	T=rd();
	while(T--){
		int n;rdint(n);
		for(int i=0;i<=n;i++)vc[i].clear();
		for(int i=1;i<n;i++){
			int fa;rdint(fa);
			vc[fa].push_back(i);
		}
		ans=0;
		for(int i=0;i<n;i++)rdint(a[i]);
		dfs(0,0,0);
		if(ans)cout<<"win"<<endl;
		else cout<<"lose"<<endl;
	}
}