1、暴力解法,遍历数组如果有这个数就停止,没有就返回FLASE.

public boolean Find(int target, int [][] array) {
            if(array.length == 0 ||target < 0 ){
                return false;
            }
            for(int i = 0; i<array.length;i++){
                for(int j = 0;j<array[0].length;j++){
                    if(array[i][j] == target)
                        return true;
                }
            }
            return false;
    }
    2、寻找规律,从右上角开始依次查询  排除数字不能出现的区域  
      public boolean Find(int target, int [][] array) {
        if(array.length-1 == 0 ){return false;}
        int row = 0;
        int column = array[0].length-1;
        boolean s = false;
        while(row < array.length&&column>=0){
            if(array[row][column] == target){
                s = true;
                break;
            }if(array[row][column]>target){
                    column--;
                }else {
                row++;
               }
        }
        return s;
    }