python递归求阶乘

# 递归求阶乘

def mi(num):
    if(num==1 or num==0):
        return 1
    else:
        return num*mi(num-1)
for i in range(6):
     print(mi(i))
#print(mi(3)) def fact(j): sum = 0 if j == 0: sum = 1 else: sum = j * fact(j - 1) return sum for i in range(6): print('%d! = %d' % (i,fact(i)))

  

posted @ 2018-04-07 16:32  zxf123  阅读(309)  评论(0编辑  收藏  举报