js获取链接?后边的参数名称或者值
1.获取后边的参数名称<script type="text/javascript">
var url = location.search; //获取url中"?"符后的字串 ,包括? console.log(url); function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if(url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i++) { theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); } } return theRequest; } var Request = undefined; Request = GetRequest(); console.log(Request);//最后获取的字段名+值 const keys= Object.keys(Request); console.log(keys);//数组 console.log(keys[0]);//输出a </script>
2.获取?后边参数值:
function getQueryString(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); var r = window.location.search.substr(1).match(reg); if (r != null) return unescape(r[2]); return null; } //例子 var contest_id = getQueryString("contest_id");