2.add two numbers

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.
# Definition for singly-linked list.


# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None




class Solution:

    def addTwoNumbers(self, l1, l2):
        """
        :type l1: ListNode
        :type l2: ListNode
        :rtype: ListNode
        """
        dummy=cur=ListNode(0)
        carry=0
        while l1 or l2 or carry: 
            if l1:
                carry+=l1.val
                l1=l1.next
            if l2:
                carry+=l2.val
                l2=l2.next
                
            cur.next=ListNode(carry%10)
            cur=cur.next
            carry//=10
        return dummy.next

posted @ 2018-06-13 00:30  zx-y  阅读(101)  评论(0编辑  收藏  举报