Get the parameter from the URL
摘要：
1 2 sUrl = location.search; 3 sIndex = sUrl.indexOf( " ?url= " ); 4 if (sIndex != - 1 ) 5 {6sUrl=sUrl.substring(sIndex+5,sUrl.length);7} 8 ... 阅读全文
posted @ 2007-02-01 16:12 广思 阅读(334) 评论(0) 推荐(0) 编辑
