LC-34
package getSecondBiggestNum.nums;
public class LC34 {
public int[] searchRange(int[] nums, int target) {
int temp = binarySearch(nums, target);
int[] ints = new int[]{-1, -1};
if (temp == -1) {
return ints;
} else if (nums.length <= 2) {
//pass
} else if (nums[temp - 1] == target) {
ints[0] = temp - 1;
ints[1] = temp;
return ints;
} else if (nums[temp + 1] == target) {
ints[0] = temp;
ints[1] = temp + 1;
return ints;
}
return ints;
}
/**
* @param nums
* @param target
* @return
*/
public int binarySearch(int[] nums, int target) {
int left = 0;
int right = nums.length - 1;
while (left <= right) {
int middle = left + ((right - left) / 2);
if (nums[middle] < target) {
left = middle + 1;
} else if (nums[middle] > target) {
right = middle - 1;
} else {
return middle;
}
}
return -1;
}
}
注意:pass部分,在 nums[ ] 元素少于等于俩个的时候会有多种”意外“。
容易混淆自己。
一个二分来查找左右边界,很容易把自己绕进去,建议扎扎实实的写两个二分分别找左边界和右边界。
class Solution {
int[] searchRange(int[] nums, int target) {
int leftBorder = getLeftBorder(nums, target);
int rightBorder = getRightBorder(nums, target);
// 情况一
if (leftBorder == -2 || rightBorder == -2) return new int[]{-1, -1};
// 情况三
if (rightBorder - leftBorder > 1) return new int[]{leftBorder + 1, rightBorder - 1};
// 情况二
return new int[]{-1, -1};
}
int getRightBorder(int[] nums, int target) {
int left = 0;
int right = nums.length - 1;
int rightBorder = -2; // 记录一下rightBorder没有被赋值的情况
while (left <= right) {
int middle = left + ((right - left) / 2);
if (nums[middle] > target) {
right = middle - 1;
} else { // 寻找右边界,nums[middle] == target的时候更新left
left = middle + 1;
rightBorder = left;
}
}
return rightBorder;
}
int getLeftBorder(int[] nums, int target) {
int left = 0;
int right = nums.length - 1;
int leftBorder = -2; // 记录一下leftBorder没有被赋值的情况
while (left <= right) {
int middle = left + ((right - left) / 2);
if (nums[middle] >= target) { // 寻找左边界,nums[middle] == target的时候更新right
right = middle - 1;
leftBorder = right;
} else {
left = middle + 1;
}
}
return leftBorder;
}
}