摘要: 题意 "题目链接" Sol 直接把$q_i$除掉 那么$E_j = \sum_{i = 1}^{j 1} q_i \frac{1}{(i j)^2} \sum_{i = j + 1}^n q_i \frac{1}{(i j)^2}$ 设$f_i = q_i, g_i = \frac{1}{i^2}$ 阅读全文
posted @ 2018-11-26 22:27 自为风月马前卒 阅读(238) 评论(0) 推荐(0) 编辑

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