2017.9.23清北第二场 

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<queue>
 6 using namespace std;
 7 const int MAXN=400001;
 8 inline void read(int &n)
 9 {
10     char c=getchar();n=0;bool flag=0;
11     while(c<'0'||c>'9')    c=='-'?flag=1,c=getchar():c=getchar();
12     while(c>='0'&&c<='9')    n=n*10+c-48,c=getchar();flag==1?n=-n:n=n;
13 }
14 int n,m,bgx,bgy,k;
15 int s,x,z,y;
16 int flag=0;
17 int nowx=1,nowy=1;
18 int nowstep=0;
19 int pd()
20 {
21     if(flag==1)        nowstep++;
22     if(nowx==bgx&&nowy==bgy)    flag=1;
23     if(nowstep==k)    printf("%d %d",nowy-1,nowx-1),exit(0);
24 }
25 int main()
26 {
27     freopen("calc.in","r",stdin);
28     freopen("calc.out","w",stdout);
29     read(n);read(m);read(bgx);read(bgy);read(k);
30     if(k==0)    printf("%d %d",bgx,bgy),exit(0);
31     swap(bgx,bgy);bgx++;bgy++;swap(n,m);
32     
33     s=1,x=n,z=1,y=m;
34     while(s<=n&&x>=1&&z<=m&&y>=1)
35     {
36         while(nowy<y)    
37         nowy++,pd();    s++;
38         while(nowx<x)    
39         nowx++,pd();    y--;
40         while(nowy>z)    
41         nowy--,pd();    x--;
42         while(nowx>s)    
43         nowx--,pd();    z++;
44     }
45     return 0;
46 }
T1
 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<queue>
 6 using namespace std;
 7 const int MAXN=200001;
 8 inline void read(int &n)
 9 {
10     char c=getchar();n=0;bool flag=0;
11     while(c<'0'||c>'9')    c=='-'?flag=1,c=getchar():c=getchar();
12     while(c>='0'&&c<='9')    n=n*10+c-48,c=getchar();flag==1?n=-n:n=n;
13 }
14 int T,n;
15 int ans[MAXN];
16 int a[MAXN];
17 int main()
18 {
19     freopen("sum.in","r",stdin);
20     freopen("sum.out","w",stdout);
21     read(T);
22     while(T--)
23     {
24         read(n);
25         for(int i=1;i<=n;i++)    read(a[i]);
26         for(int i=1;i<=n;i++)
27         {
28             int nowmax=-0x7fff,nowmin=0x7fff;
29             for(int j=i;j<=n;j++)
30                 nowmin=min(nowmin,a[j]),
31                 nowmax=max(nowmax,a[j]),
32                 ans[nowmax-nowmin]++;
33         }
34         for(int i=1;i<=n-1;i++)    ans[i]+=ans[i-1];
35         for(int i=0;i<=n-1;i++)
36             printf("%d\n",ans[i]);
37     }
38     return 0;
39 }
T2
 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<queue>
 6 using namespace std;
 7 const int MAXN=400001;
 8 const int mod=1000000007;
 9 inline void read(int &n)
10 {
11     char c=getchar();n=0;bool flag=0;
12     while(c<'0'||c>'9')    c=='-'?flag=1,c=getchar():c=getchar();
13     while(c>='0'&&c<='9')    n=n*10+c-48,c=getchar();flag==1?n=-n:n=n;
14 }
15 int T,n,m,k;
16 int vis[MAXN];
17 int happen[MAXN];
18 int ans=0;
19 void dfs(int now)
20 {
21     if(now==n+1)    
22     {ans=(ans+1)%mod;return ;}
23     if(vis[now])    dfs(now+1);
24     for(int i=now-k;i<=now+k;i++)
25     {
26         if(!happen[i]&&i>=1&&i<=n)
27         {
28             happen[i]=1;
29             dfs(now+1);
30             happen[i]=0;    
31         }
32     }
33     
34 }
35 int main()
36 {
37     freopen("count.in","r",stdin);
38     freopen("count.out","w",stdout);
39     read(T);
40     while(T--)
41     {
42         ans=0;
43         read(n);read(m);read(k);bool flag=0;
44         if(k==0)
45         {
46             printf("1");
47             continue;
48         }    
49         for(int i=1;i<=m;i++)
50         {
51             int x,y;read(x);read(y);
52             vis[x]=1;happen[y]=1;
53             if(abs(y-x)>k)    
54             {    flag=1;break;    }
55         }
56         if(!flag)    dfs(1);
57         printf("%d\n",ans%mod);
58     }
59     return 0;
60 }
T3

 

posted @ 2017-09-23 11:46  自为风月马前卒  阅读(212)  评论(0)  编辑  收藏  举报

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