HDU 5733 tetrahedron
计算几何。先判四点是否共面,共面则无解。然后计算出圆心坐标,然后计算圆心到任意一面的距离。
#include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map> #include<set> #include<queue> #include<stack> #include<iostream> using namespace std; typedef long long LL; #define eps 1e-8 #define zero(x) (((x)>0?(x):-(x))<eps) struct point3 { double x,y,z; }; struct line3 { point3 a,b; }; struct plane3 { point3 a,b,c; }; //计算 cross product product product product U x V point3 xmult(point3 u,point3 v) { point3 ret; ret.x=u.y*v.z-v.y*u.z; ret.y=u.z*v.x-u.x*v.z; ret.z=u.x*v.y-u.y*v.x; return ret; } //计算 dot product product product product U . V double dmult(point3 u,point3 v) { return u.x*v.x+u.y*v.y+u.z*v.z; } //矢量差 U - V point3 subt(point3 u,point3 v) { point3 ret; ret.x=u.x-v.x; ret.y=u.y-v.y; ret.z=u.z-v.z; return ret; } //取平面法向量 point3 pvec(plane3 s) { return xmult(subt(s.a,s.b),subt(s.b,s.c)); } point3 pvec(point3 s1,point3 s2,point3 s3) { return xmult(subt(s1,s2),subt(s2,s3)); } //两点距离,单参数取向量大小 double dis(point3 p1,point3 p2) { return sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y)+(p1.z-p2.z)*(p1.z-p2.z)); } //向量大小 double vlen(point3 p) { return sqrt(p.x*p.x+p.y*p.y+p.z*p.z); } int dots_onplane(point3 a,point3 b,point3 c,point3 d) { return zero(dmult(pvec(a,b,c),subt(d,a))); } //点到平面距离 double ptoplane(point3 p,point3 s1,point3 s2,point3 s3) { return fabs(dmult(pvec(s1,s2,s3),subt(p,s1)))/vlen(pvec(s1,s2,s3)); } double Area(point3 a,point3 b,point3 c) { double ab=dis(a,b),bc=dis(b,c),ac=dis(a,c); double p=(ab+bc+ac)/2; return sqrt(p* (p-ab) * (p-bc)*(p-ac)); } int main() { point3 p[5]; while(~scanf("%lf%lf%lf",&p[1].x,&p[1].y,&p[1].z)) { for(int i=2;i<=4;i++) scanf("%lf%lf%lf",&p[i].x,&p[i].y,&p[i].z); if(dots_onplane(p[1],p[2],p[3],p[4])) { printf("O O O O\n"); continue; } double Sabc=Area(p[1],p[2],p[3]); double Sabd=Area(p[1],p[2],p[4]); double Sacd=Area(p[1],p[3],p[4]); double Sbcd=Area(p[2],p[3],p[4]); double S=Sabc+Sabd+Sacd+Sbcd; point3 heart; heart.x=( Sabc*p[4].x+Sabd*p[3].x + Sacd*p[2].x+Sbcd*p[1].x)/S; heart.y=( Sabc*p[4].y+Sabd*p[3].y + Sacd*p[2].y+Sbcd*p[1].y)/S; heart.z=( Sabc*p[4].z+Sabd*p[3].z + Sacd*p[2].z+Sbcd*p[1].z)/S; printf("%.4lf %.4lf %.4lf %.4lf\n",heart.x,heart.y,heart.z,ptoplane(heart,p[1],p[2],p[3])); } return 0; }