POJ 3905 Perfect Election
2-SAT 裸题,搞之
#include<cstdio> #include<cstring> #include<cmath> #include<stack> #include<vector> #include<algorithm> using namespace std; const int maxn=2000+10; int N,M; char s1[100],s2[100]; stack<int>S; vector<int>G[maxn]; vector<int>FG[maxn]; int Belong[maxn]; int flag[maxn]; int Block; void init() { for(int i=0; i<maxn; i++) G[i].clear(); for(int i=0; i<maxn; i++) FG[i].clear(); memset(Belong,0,sizeof Belong); memset(flag,0,sizeof flag); while(!S.empty()) S.pop(); Block=0; } void addEgde(int x,int y) { G[x].push_back(y); FG[y].push_back(x); } void dfs1(int now) { flag[now]=1; for(int i=0; i<G[now].size(); i++) if(!flag[G[now][i]]) dfs1(G[now][i]); S.push(now); } void dfs2(int now) { Belong[now]=Block; for(int i=0; i<FG[now].size(); i++) if(!Belong[FG[now][i]]) dfs2(FG[now][i]); } bool judge() { for(int i=0; i<2*N; i++) if(!flag[i]) dfs1(i); while(!S.empty()) { int Top=S.top(); S.pop(); if(!Belong[Top]) { Block++; dfs2(Top); } } for(int i=0; i<N; i++) if(Belong[2*i]==Belong[2*i+1]) return 0; return 1; } int main() { while(~scanf("%d%d",&N,&M)) { init(); for(int i=1;i<=M;i++) { scanf("%s%s",s1,s2); int num1=0,num2=0; for(int i=1;i<strlen(s1);i++) num1=num1*10+s1[i]-'0'; for(int i=1;i<strlen(s2);i++) num2=num2*10+s2[i]-'0'; num1--;num2--; if(s1[0]=='+'&&s2[0]=='+') { addEgde(2*num1,2*num2+1); addEgde(2*num2,2*num1+1); } if(s1[0]=='-'&&s2[0]=='-') { addEgde(2*num1+1,2*num2); addEgde(2*num2+1,2*num1); } if(s1[0]=='+'&&s2[0]=='-') { addEgde(2*num1,2*num2); addEgde(2*num2+1,2*num1+1); } if(s1[0]=='-'&&s2[0]=='+') { addEgde(2*num1+1,2*num2+1); addEgde(2*num2,2*num1); } } if(judge()) printf("1\n"); else printf("0\n"); } return 0; }