题意:
获得集合中最长前缀长度*有该前缀个数的最大值
example the prefix goodness of the set {000,001,0011} is 6.You are given a set of binary strings. Find
the maximum prefix goodness among all possible subsets of these binary strings.
Input
First line of the input contains T(<=20) the number of test cases. Each of the test cases start with n (<=50000) the number of strings. Each of the next n
lines contains a string containing only '0' and '1'.Maximum length of each of these string is 200.
Output
For each test case output the maximum prefix goodness among all possible subsets of n binary strings.
SampleInput
4
4
0000
0001
10101
010
2
01010010101010101010
11010010101010101010
3
010101010101000010001010
010101010101000010001000
010101010101000010001010
5
01010101010100001010010010100101
01010101010100001010011010101010
00001010101010110101
0001010101011010101
00010101010101001
SampleOutput
6
20
66
44
#include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int sum; char str[205]; struct Trie { int cnt; Trie *next[5]; Trie() { cnt=0; memset(next,NULL,sizeof(next)); } }; void Insert(Trie *p,char ch[],int len) { for(int i=0;i<strlen(ch);i++) { p->cnt++; sum = max(sum,p->cnt*i); if(p->next[ ch[i]-'0' ]==NULL) p->next[ ch[i]-'0']=new Trie; p = p->next[ch[i]-'0']; } p->cnt++; sum = max(sum,p->cnt*(int)strlen(ch)); } int main() { int T,n; scanf("%d",&T); while(T--) { scanf("%d",&n); Trie *root=new Trie; sum=0; while(n--) { scanf("%s",str); Insert(root,str,0); } printf("%d\n",sum); } return 0; }