「NOIP2018」赛道修建

传送门
Luogu

解题思路

一眼先二分(上界树的直径,下界最小边权),然后再考虑 \(\text{DP}\)
对于当前节点 \(u\),在它的所有儿子中分别返回一条匹配不完的长度最大的路径 \(Max\)
若该路径长大于二分值,直接修一条,不然丢进 \(\text{multiset}\) 里面。
对于 \(\text{multiset}\) 里的元素每次贪心的找出尽可能大的一条与最小的匹配,若找不到则用来更新 \(Max\)
\(check\) 函数里面返回 \(ans\ge m\),最后输出答案即可。

细节注意事项

  • \(\text{multiset}\) 的使用要熟练

参考代码

#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <cctype>
#include <cmath>
#include <ctime>
#include <set>
#define rg register
using namespace std;
template < typename T > inline void read(T& s) {
	s = 0; int f = 0; char c = getchar();
	while (!isdigit(c)) f |= (c == '-'), c = getchar();
	while (isdigit(c)) s = s * 10 + (c ^ 48), c = getchar();
	s = f ? -s : s;
}

const int _ = 50010;
const int __ = 100010;

int tot, head[_], nxt[__], ver[__], w[__];
inline void Add_edge(int u, int v, int d)
{ nxt[++tot] = head[u], head[u] = tot, ver[tot] = v, w[tot] = d; }

int n, m, ans;
multiset < int > S[_];
multiset < int > ::iterator it;

inline int dfs(int u, int f, int mid) {
	S[u].clear();
	for (rg int i = head[u]; i; i = nxt[i]) {
		int v = ver[i]; if (v == f) continue;
		int res = dfs(v, u, mid) + w[i];
		if (res >= mid) ++ans; else S[u].insert(res);
	}
	int _max = 0;
	while (!S[u].empty()) {
		if (S[u].size() == 1)
			return _max = max(_max, *S[u].begin());
		it = S[u].lower_bound(mid - *S[u].begin());
		if (it == S[u].begin() && S[u].count(*it) == 1) ++it;
		if (it == S[u].end()) {
			_max = max(_max, *S[u].begin());
			S[u].erase(S[u].find(*S[u].begin()));
		} else {
			++ans;
			S[u].erase(S[u].find(*it));
			S[u].erase(S[u].find(*S[u].begin()));
		}
	}
	return _max;
}

inline bool check(int mid)
{ ans = 0, dfs(1, 0, mid); return ans >= m; }

int _min = 100000, _max, id;

inline void dfs_d(int u, int f, int sum) {
	if (sum > _max) _max = sum, id = u;
	for (rg int i = head[u]; i; i = nxt[i]) {
		int v = ver[i]; if (v == f) continue;
		_min = min(_min, w[i]), dfs_d(v, u, sum + w[i]);
	}
}

inline void get_d() { dfs_d(1, 0, 0), _max = 0, dfs_d(id, 0, 0); }

int main() {
#ifndef ONLINE_JUDGE
	freopen("in.in", "r", stdin);
#endif
	read(n), read(m);
	for (rg int u, v, d, i = 1; i < n; ++i)
		read(u), read(v), read(d), Add_edge(u, v, d), Add_edge(v, u, d);
	
	get_d();
	
	int l = _min, r = _max;
	while (l < r) {
		int mid = (l + r + 1) >> 1;
		if (check(mid)) l = mid;
		else r = mid - 1;
	}
	
	printf("%d\n", l);
	return 0;
}

完结撒花 \(qwq\)

posted @ 2019-10-26 22:06  Sangber  阅读(263)  评论(0编辑  收藏  举报