日期计算

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#include<stdio.h> #include<iostream> using namespace std; //日期函数   int days[12]={31,28,31,30,31,30,31,31,30,31,30,31}; struct date{     int year,month,day; };   //判闰年 inline int leap(int year){     return (year%4==0&&year%100!=0)||year%400==0; }   //判合法性 inline int legal(date a){     if (a.month<0||a.month>12)         return 0;     if (a.month==2)         return a.day>0&&a.day<=28+leap(a.year);     return a.day>0&&a.day<=days[a.month-1]; }   //比较日期大小 inline int datecmp(date a,date b){    if (a.year!=b.year)        return a.year-b.year;    if (a.month!=b.month)        return a.month-b.month;    return a.day-b.day; }   //返回指定日期是星期几 int weekday(date a){     int tm=a.month>=3?(a.month-2):(a.month+10);     int ty=a.month>=3?a.year:(a.year-1);     return (ty+ty/4-ty/100+ty/400+(int)(2.6*tm-0.2)+a.day)%7; }   //日期转天数偏移 int date2int(date a){     int ret=a.year*365+(a.year-1)/4-(a.year-1)/100+(a.year-1)/400,i;     days[1]+=leap(a.year);     for (i=0;i<a.month-1;ret+=days[i++]);     days[1]=28;     return ret+a.day; }   //天数偏移转日期 date int2date(int a){     date ret;     ret.year=a/146097*400;     for (a%=146097;a>=365+leap(ret.year);a-=365+leap(ret.year),ret.year++);     days[1]+=leap(ret.year);     for (ret.month=1;a>=days[ret.month-1];a-=days[ret.month-1],ret.month++);     days[1]=28;     ret.day=a+1;     return ret; }   int main() {     date a,b;     a.year=2014,a.month=8,a.day=28;     b.year=2014,b.month=8,b.day=29;     //计算日期之间相差多少天     int t1=date2int(a);//a的天数     int t2=date2int(b);//b的天数     printf("%d\n",t2-t1);     //计算当前日期过了day天的日期     int day=1;     date c=int2date(day+t1);     printf("%d %d %d",c.year,c.month,c.day);     return 0; }