UVa Automatic Editing

uva的题真的很好，每个题都能长许多知识，A了后很开心，这道题我用了两天写，只一道题就学了四个函数，成长不少

Problem E: Automatic Editing

Source file:	autoedit.{c, cpp, java, pas}
Input file:	autoedit.in
Output file:	autoedit.out

Text-processing tools like awk and sed allow you to automatically perform a sequence of editing operations based on a ｓcript. For this problem we consider the specific case in which we want to perform a series of string replacements, within a single line of text, based on a fixed set of rules. Each rule specifies the string to find, and the string to replace it with, as shown below.

 

Rule	Find	Replace-by
1.	ban	bab
2.	baba	be
3.	ana	any
4.	ba b	hind the g

 

To perform the edits for a given line of text, start with the first rule. Replace the first occurrence of the find string within the text by thereplace-by string, then try to perform the same replacement again on the new text. Continue until the find string no longer occurs within the text, and then move on to the next rule. Continue until all the rules have been considered. Note that (1) when searching for a findstring, you always start searching at the beginning of the text, (2) once you have finished using a rule (because the find string no longer occurs) you never use that rule again, and (3) case is significant.

For example, suppose we start with the line

 

banana boat

 

and apply these rules. The sequence of transformations is shown below, where occurrences of a find string are underlined and replacements are boldfaced. Note that rule 1 was used twice, then rule 2 was used once, then rule 3 was used zero times, and then rule 4 was used once.

 

	Before	After
	banana boat	babana boat
	babana boat	bababa boat
	bababa boat	beba boat
	beba boat	behind the goat

 

The input contains one or more test cases, followed by a line containing only 0 (zero) that signals the end of the file. Each test case begins with a line containing the number of rules, which will be between 1 and 10. Each rule is specified by a pair of lines, where the first line is the find string and the second line is the replace-by string. Following all the rules is a line containing the text to edit. For each test case, output a line containing the final edited text.

Both find and replace-by strings will be at most 80 characters long. Find strings will contain at least one character, but replace-bystrings may be empty (indicated in the input file by an empty line). During the edit process the text may grow as large as 255 characters, but the final output text will be less than 80 characters long.

The first test case in the sample input below corresponds to the example shown above.

Example input:

4
ban
bab
baba
be
ana
any
ba b
hind the g
banana boat
1
t
sh
toe or top
0

Example output:

behind the goat
shoe or shop

题意：替换，在再字符窜中找到能够替换的就替换。

 Note that (1) when searching for a findstring, you always start searching at the beginning of the text, (2) once you have finished using a rule (because the find string no longer occurs) you never use that rule again, and (3) case is significant.

For example, suppose we start with the line。找到一个就重新开始，一旦结束了一个语法就不能在使用了。题意。。。。

#include<stdio.h>
#include<string.h>
struct Node
{
    int len1,len2;
    char nam1[100],nam2[100];
}word[100];

int main()
{
    int n,i,j;
    char *pt,*px;
    char str[500],rem[500],ss[500];
    int cas,flag;
    while(scanf("%d",&n) && n)
    {
        getchar();
        for (i=0;i<n;i++)
        {
            gets(word[i].nam1);
            word[i].len1=strlen(word[i].nam1);
            gets(word[i].nam2);
            word[i].len2=strlen(word[i].nam2);
        }
        gets(str);
        strcpy(rem,str);
        for (i=0;i<n;i++)//单词个数
        {
            flag=0;
            pt=strstr(rem,word[i].nam1);
            if(pt!=NULL) flag=1;
            else continue;
            cas=0;
            for (px=rem;px!=pt;px++)//存储前半部分
            {
                ss[cas++]=*px;
            }
            ss[cas]='\0';
            pt+=word[i].len1;//抛弃该换掉的地方
            strcat(ss,word[i].nam2);//接入新的
            strcat(ss,pt);//接入剩余部分
            strcpy(rem,ss);
            if(flag) i-=1;
        }
        printf("%s\n",rem);
    }
    return 0;
}