随笔分类 - codeforces
1738C-Even Number Addicts - dp, games, greedy
摘要：void solve() { int n; cin >> n; int odd = 0, even = 0; for (int i = 0; i < n; i++) { int a; cin >> a; if (a & 1) odd++; else even++; } int t = odd & 3
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