11 2022 档案
摘要：int main(){ int i; int count = 0; for (i = 1000; i <= 2000; i++) { if (i % 4 == 0 && i%100 !=0) { printf("1000-2000年之间的闰年：%d\n", i); count++; } else i
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摘要：int main(){ int i = 0; float w, e, l; char char_com = '0'; while(char_com !='p') { float win = 0.0; float even = 0.0; float lose = 0.0; float prcp = 0
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摘要：int main(){ int a = 0; int b = 0; scanf("%d,%d", &a, &b); if (a < b) { int tmp = 0; tmp = a; a = b; b = tmp; } while (a % b != 0)//可以用while（tmp=a%b）代替
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摘要：int main() { int a, b,i; int tmp = 0; printf("请输入a&b 的值:>"); scanf("%d,%d", &a, &b); if (a < b) { tmp = a; a = b; b = tmp; } for (i = b; i > 0; i--) i
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摘要：int main(){ int n = 0; int i = 1; for (i = 1; i <= 100; i++) { if (i % 3 == 0) printf("%d ", i); } /*for (i = 1; n < 99; i++) { n = i * 3; printf("%d
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摘要：int main(){ int a = 0; int b = 0; int c = 0; scanf("%d,%d,%d", &a, &b, &c); if (a < b) { int tmp = a; a = b; b = tmp; } if (a < c) { int tmp = a; a =
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摘要：int main(){ int i = 0; char password[20] = { 0 }; for (i = 0; i < 3; i++) { printf("请输入密码："); scanf("%s", password); //if (password == "123456")//==不能
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摘要：int main(){ char arr1[] = "welcome to bit!!!!!!!"; char arr2[] = "#####################"; int left = 0; //int sz = sizeof(arr1) / sizeof(arr1[0]);//数组
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摘要：int main(){ int arr[] = { 1,2,3,4,5,6,7,8,9,10 }; int n = 7; int sz = sizeof(arr) / sizeof(arr[0]); int left = 0; int right = sz - 1; while (left<=rig
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摘要：int main(){ int i, n; double ret = 1; double sum = 0; //scanf("%d", &n); for (n = 1; n <= 3; n++) { ret = ret * n;//n的阶乘 sum = ret + sum;//n阶乘的和 } pri
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摘要：int main(){ int i = 1; do { if (5 == i)//不可在循环体内更改循环变量，防止循环失控，例：if（i=5） continue;//满足if条件为真，继续返回前面的语句，而本次循环continue后面的代码终止执行。 //break;//满足if条件为真，跳出循环；
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摘要：int main(){ int x, y; for (x = 0, y = 0; y = 0; x++, y++)//0为假 { printf("hehe\n"); } return 0;}//int main()//{// int i = 0;// int e = 0;// for (; i <
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摘要：int main(){ int ch = 0; int ret = 0; char password[20] = {0}; printf("请输入密码:>"); scanf("%s", password);//按回车时，被getchar获取，回车=\n,ASCII \n的值为10，所以后面执行els
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摘要：int main(){ int i = 1; while (i <= 10) { //if (5 == i) //continue;//满足if条件为真，继续返回前面的循环判断语句，而本次循环continue后面的代码终止执行。 //break;//满足if条件为真，跳出循环；永久终止循环。 pri
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摘要：//struct MAN//{// char name[20];// short age;// int tel;////};//int main()//{// struct MAN a = { "张仁魁",29,1508888888 };// struct MAN* pb = &a;//指针取地址/
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摘要：int main()//{// int a = 4;// if (5 == a)//一个等号是赋值，==为判断，所以产生bug；// //解决方案：常量放前面，变量放后面（5==a），及时纠错// {// printf("HEHE\n");// }//// return 0;//}//int mai
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摘要：//int main()//{// int day = 0;// printf("星期几：");// scanf("%d",&day);// switch (day)//应用（整形、字符、enum类型）// {//要有大括号来包括整个switch内容// case 1:printf("星期1\n")
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