form表单发送请求方式

1，直接用表单的 action 属性跳转路由，此方法必须各节点的name属性和 Java bean 实体类属性相对应，并且onsubmit 属性不为false。

优点：快速，简单跳转路由。

缺点：返回数据不好处理，前后台交互繁琐。

<form name="mdShopuser.form" action="/ShopUser/ShopUserGoin" method="POST" autocomplete="off" onsubmit="return validate()">
           <div class="info-name">
               <span>* 姓名</span>
               <input type="text"  name="mdShopuser.Name" value="" autofocus="autofocus" >
           </div>
           <div class="info-name">
               <span>* 手机号</span>
               <input type="text" value="" name="mdShopuser.Phone">
           </div>
           <div class="info-name">
               <span>* 店铺名称</span>
               <input type="text" value="" name="mdShopuser.ShopName">
               <div class="info-name">
                   <span>* 行业类别</span>
                   <input type="text" value="" name="mdShopuser.SalesPikd">
               </div>
               <div class="info-name">
                   <span>* 店铺地址</span>
                   <input type="text" value="" name="mdShopuser.ShopAddress">
               </div>
               <div class="info-name">
                   <span>详细地址</span>
                   <input type="text" value="" name="mdShopuser.DetailAddress">
               </div>
               <div class="reason">
                   <span>申请理由</span><br>
                   <textarea type="text" name="" rows="5" name="mdShopuser.Application"></textarea>
               </div>
               <div>
                   <button type="submit">提交申请</button>
               </div>
           </div>
       </form>

　2.　第二种方式是表单序列化提交此方式onsubmit=false：就是不允许使用action，===》此方式使用点击事件结合ajax 提交表单

优点：前后台交互方便，后台给前台数据好处理。

缺点：需要结合ajax使用。

<form id="member_form" onsubmit="return false" method="POST">
    <div class="login-info login-name">
        <i class="fa fa-user-o"></i>
        <input type="text" value="" autofocus="autofocus" name="member.number_id" placeholder="请输入账号" id="input_username">
    </div>
    <div class="login-info login-pwd">
        <i class="fa fa-lock" aria-hidden="true"></i>
        <input type="password" value="" name="member.password" placeholder="请输入密码" id="input_password">
        <img src="/_view/_web/img/icon3.png" alt="" onclick="show()">
    </div>
    <div class="login-reg">
        <span><a href="/_view/_web/register/notMemberRegister.html">免费注册</a></span>
    </div>
    <div class="login-btn">
        <button onclick="btn()">登录</button>
    </div>
</form>

// 提交表单前验证用户名密码不能为空
function btn() {
        $.ajax({
            type:"POST",
            dataType:"json",
            url:"/login/memberLogin",
            data:$("#member_form").serialize(),
            success:function (result) {
                console.log(result.status)
                if (result.status == "ok") {
                    window.location.href = "/login/tovip"
                }else if(result.status == "false"){
                    layer.msg("该账号还未审核，暂时无法登录",{time:1000})
                }else if (result.status == "false1"){
                    layer.msg("账号或密码错误",{time:1500})
                }
            },
            error:function (err) {
                layer.msg("账号或密码错误",{time:1000})
            }
        })
    }

}