A C

Problem Description

Are you excited when you see the title "AC" ? If the answer is YES , AC it ;

You must learn these two combination formulas in the school . If you have forgotten it , see the picture.




Now I will give you n and m , and your task is to calculate the answer .

 

Input

In the first line , there is a integer T indicates the number of test cases.
Then T cases follows in the T lines.
Each case contains a character 'A' or 'C', two integers represent n and m. (1<=n,m<=10)

 

Output

For each case , if the character is 'A' , calculate A(m,n),and if the character is 'C' , calculate C(m,n).
And print the answer in a single line.

 

Sample Input

2

A 10 10

C 4 2

 

Sample Output

3628800

6

 

#include <stdio.h>

int jieCheng(int number);

int main(){
    int T;
    char c;
    int n;
    int m;
    int n_jieCheng;
    int m_jieCheng;
    int n_m_jieCheng;
    int result;
    
    scanf("%d",&T);
    
    while(T--){
        getchar();
        
        scanf("%c%d%d",&c,&n,&m);
        
        n_jieCheng=jieCheng(n);
        m_jieCheng=jieCheng(m);
        n_m_jieCheng=jieCheng(n-m);
        
        if(c=='A')
            result=n_jieCheng/n_m_jieCheng;
        
        else
            result=n_jieCheng/(m_jieCheng*n_m_jieCheng);
            
        printf("%d\n",result);
    }
    return 0;
}

int jieCheng(int number){
    int result;
    int i;
    
    result=1;
    
    for(i=1;i<=number;i++)
        result*=i;
        
    return result;
}