An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6

R 1

P 2

G 3

r 1

p 2

g 3

 

Sample Output

19

18

10

-17

-14

-4

 

#include <stdio.h>  
#include <ctype.h>

int main(){
    int T;
    char c;
    int number;
    int result;

    scanf("%d",&T);

    while(T--){
        getchar();
        scanf("%c%d",&c,&number);

        if(islower(c)!=0){
            result=c-'a'+1;
            result=-result;
            result+=number;
        }

        else{
            result=c-'A'+1;
            result+=number;
        }

        printf("%d\n",result);
    }

    return 0;
}