摘要: 1 #递归 2 def fun(x): 3 if x>0: 4 fun(x-1) 5 print(x) 6 # fun(2) 7 8 # print(4/2) 9 # lis=[ 10 # {'id':1001, 'name':"张三", 'age':20}, 11 # {'id':1002, 'n 阅读全文
posted @ 2019-12-11 09:26 毛斯钢 阅读(194) 评论(0) 推荐(0) 编辑