实验六

#include <stdio.h>
#include <string.h> 
#define N 2        

typedef struct student {
    int id;              
    char name[20];          
    char subject[20];     
    double perf;         
    double mid;         
    double final;         
    double total;         
    char level[10];     
} STU;

void input(STU [], int);            
void output(STU [], int);            
void calc(STU [], int);               
int fail(STU [], STU [], int);        
void sort(STU [], int);                 

int main() {
    STU st[N], fst[N];    
    int k;   
    
    printf("录入学生成绩信息:\n");
    input(st, N);
    
    printf("\n成绩处理...\n");
    calc(st, N);
    
    k = fail(st, fst, N);
    sort(st, N);
    printf("\n学生成绩排名情况:\n");
    output(st, N);
    
    printf("\n不及格学生信息:\n");
    output(fst, k);
    
    return 0;
} 

void input(STU s[], int n) {
    int i;
    
    for(i = 0; i < n; i++)
        scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject,
                                      &s[i].perf, &s[i].mid, &s[i].final);
}

void output(STU s[], int n) {
       int i;
   
      printf("-----------------\n");
      printf("学号   姓名     科目   平时   期中   期末   总评   等级\n");
       for(i = 0; i<n; i++)
          printf("%d   %-6s   %-4s   %-4.0f   %-4.0f   %-4.0f   %-4.1f   %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level);
}


void calc(STU s[],int n) {
    int i;

    for(i = 0; i < n; i++) {    
        s[i].total = s[i].perf * 0.2 + 
                     s[i].mid * 0.2 +
                     s[i].final * 0.6;
        
        if(s[i].total >= 90)
          strcpy(s[i].level, "");
        else if(s[i].total >= 80)
          strcpy(s[i].level, "");
        else if(s[i].total >= 70)
          strcpy(s[i].level, ""); 
        else if(s[i].total >= 60)
          strcpy(s[i].level, "及格");
        else
          strcpy(s[i].level, "不及格");         
    }
}

int fail(STU s[], STU t[], int n) {
      int i, cnt = 0;
      
      for(i = 0; i < n; i++)
          if(s[i].total < 60)
            t[cnt++] = s[i];
            
    return cnt;
}

void sort(STU s[], int n) {
    int i, j;
    STU t;
    
    for(i = 0; i < n-1; i++)
      for(j = 0; j < n-1-i; j++)
        if(s[j].total < s[j+1].total) {
            t = s[j];
            s[j] = s[j+1];
            s[j+1] = t;
        }
}

#include <stdio.h>
#include <string.h>
#define N 10
#define M 80

typedef struct {
    char name[M];       
    char author[M];     
} Book;

int main() {
    Book x[N] = { {"《一九八四》", "乔治.奥威尔"},
                  {"《美丽新世界》", "赫胥黎"},
                  {"《昨日的世界》", "斯蒂芬.茨威格"}, 
                  {"《万历十五年》", "黄仁宇"},
                  {"《一只特立独行的猪》", "王小波"},
                  {"《百年孤独》", "马尔克斯"},
                  {"《查令十字街84号》", "海莲.汉芙"},
                  {"《只是孩子》", "帕蒂.史密斯"}, 
                  {"《刀锋》", "毛姆"},
                  {"《沉默的大多数》", "王小波"} };
    Book *ptr;
    int i;
    char author[M];
    int found;


    printf("-------------------所有图书信息-------------------\n");
    for(ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);

    
    printf("\n-------------------按作者查询图书-------------------\n");
    printf("输入作者名: ");
    gets(author);
    found = 0;
    for(ptr = x; ptr < x + N; ++ptr)
        if(strcmp(ptr->author, author) == 0) {
            found = 1;
            printf("%-30s%-30s\n", ptr->name, ptr->author);
        }
    
    if(!found) 
        printf("暂未收录该作者书籍!\n");

    return 0;
}

#include<stdio.h>
#include<stdlib.h>
#define N 80
typedef struct FilmInfo{
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo *next;
}Film;
 
void output(Film *head);
Film *insert(Film *head,int n);

int main(){
    int n;
    Film *head;
    
    head=NULL;
    printf("输入影片数目:");
    scanf("%d",&n);
    
    head=insert(head,n);
    printf("\n所有影片信息如下:\n");
    output(head);
    
    return 0;
}
Film *insert(Film *head,int n){
    int i;
    Film *p;
    
    for(i=1;i<=n;++i){
        p = (Film *)malloc(sizeof(Film)); 
        printf("请输入第%d部影片信息:",i);
        scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
        
        p->next=head;
        head=p;
    }
    return head;
}
void output(Film *head){
    Film *p;
    
    p=head;
    while(p!=NULL){
        printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
        p=p->next;
    }
}

#include<stdio.h>
#include<stdlib.h>
#define N 80
typedef struct FilmInfo{
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo *next;
}Film;
 
void output(Film *head);
Film *insert(Film *head,int n);

int main(){
    int n;
    Film *head;
    Film *p;
    
    p=(Film*)malloc(sizeof(Film));
    p->next=NULL;
    head=p;
    
    printf("输入影片数目:");
    scanf("%d",&n);
    
    head=insert(head,n);
    printf("\n所有影片信息如下:\n");
    output(head);
    
    return 0;
}
Film *insert(Film *head,int n){
    int i;
    Film *p;
    
    for(i=1;i<=n;++i){
        p = (Film *)malloc(sizeof(Film)); 
        printf("请输入第%d部影片信息:",i);
        scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
        
        p->next=head->next;
        head->next=p;
    }
    return head;
}
void output(Film *head){
    Film *p;
    
    p=head->next;
    while(p!=NULL){
        printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
        p=p->next;
    }
}

 

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}

void output(Book x[],int n){
    printf("ISBN号               书名                       作者               售价             销售册数\n");
    int i;
    for(i=0;i<n;i++){
        printf("%-20s %-26s %-18s %-16.2f %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
    }
}
// ×××


void sort(Book x[],int n){
    int i,j;
    Book t;
    for(i=0;i<n-1;++i){
        for(j=0;j<n-1-i;++j){
            if(x[j].sales_count<x[j+1].sales_count){
                t=x[j];
                x[j]=x[j+1];
                x[j+1]=t;
            }
        }
    }
}
// ×××


double sales_amount(Book x[],int n){
    double sum=0;
    int i;
    for(i=0;i<n;++i){
        sum+=x[i].sales_count*x[i].sales_price;
    }
    return sum;
}
// ×××

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

// 函数声明
void input(Date *pd);                   // 输入日期给pd指向的Date变量
int day_of_year(Date d);                // 返回日期d是这一年的第多少天
int compare_dates(Date d1, Date d2);    // 比较两个日期: 
                                        // 如果d1在d2之前,返回-1;
                                        // 如果d1在d2之后,返回1
                                        // 如果d1和d2相同,返回0

void test1() {
    Date d;
    int i;

    printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);
        
        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

// 补足函数input实现
// 功能: 输入日期给pd指向的Date变量
void input(Date *pd) {
    scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}

// 补足函数day_of_year实现
// 功能:返回日期d是这一年的第多少天
int day_of_year(Date d) {
    int days;
    int day_of_month[]={31,28,31,30,31,30,31,31,30,31,30,31};
    if(d.month==1){
        days=d.day;
    }
    else if(d.month==2){
        days=d.day+31;
    }
    else{
        int i;
        if((d.year%4==0&&d.year%100!=0)||(d.year%400==0)){
            for(i=0;i<(d.month-1);i++){
                days+=day_of_month[i];
            }
            days+=d.day+1;
        }
        else{
            for(i=0;i<(d.month-1);i++){
                days+=day_of_month[i];
            }
            days+=d.day;
        }
    }
    return days;
}

// 补足函数compare_dates实现
// 功能:比较两个日期: 
// 如果d1在d2之前,返回-1;
// 如果d1在d2之后,返回1
// 如果d1和d2相同,返回0
int compare_dates(Date d1, Date d2) {
    if(d1.year==d2.year){
        if(d1.month>d2.month)
           return 1;
        else if(d1.month<d2.month)
            return -1;
        else{
          if(d1.day>d2.day)
               return 1;
          else if(d1.day<d2.day)
            return -1;
          else
            return 0;
        }
           
    }
    else if(d1.year>d2.year)
       return 1;
    else
       return -1;
}

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};

typedef struct {
    char username[20];  // 用户名
    char password[20];  // 密码
    enum Role type;     // 账户类型
} Account;


// 函数声明
void output(Account x[], int n);    // 输出账户数组x中n个账户信息,其中,密码用*替代显示

int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student}, 
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);

    return 0;
}

// 待补足的函数output()实现
// 功能:遍历输出账户数组x中n个账户信息
//      显示时,密码字段以与原密码相同字段长度的*替代显示
void output(Account x[], int n) {
    int i,j;
    for(i=0;i<n;++i){
        printf("%-10s",x[i].username);
        for(j=0;j<(int)strlen(x[i].password);++j){
            printf("*");
    }
        printf("\t");
        if(x[i].type==student)
           printf("student\n");
        else if(x[i].type==admin)
           printf("admin\n");
        else
           printf("teacher\n");
    }
    
}

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];      // 姓名
    char phone[12];     // 手机号
    int  vip;           // 是否为紧急联系人,是取1;否则取0
} Contact; 


// 函数声明
void set_vip_contact(Contact x[], int n, char name[]);  // 设置紧急联系人
void output(Contact x[], int n);    // 输出x中联系人信息
void display(Contact x[], int n);   // 按联系人姓名字典序升序显示信息,紧急联系人最先显示


#define N 10
int main() {
    Contact list[N] = {{"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0}};
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n"); 
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}

// 补足函数set_vip_contact实现
// 功能:将联系人数组x中,联系人姓名与name一样的人,设置为紧急联系人(即成员vip值设为1)
void set_vip_contact(Contact x[], int n, char name[]) {
    int i;
    for(i=0;i<n;++i){
        if((int)strcmp(x[i].name,name)==0){
            x[i].vip=1;
        }
    }
}

// 补足函数display实现
// 功能: 显示联系人数组x中的联系人信息
//      按姓名字典序升序显示, 紧急联系人显示在最前面
void display(Contact x[], int n) {
    Contact temp;
    int i,j;
    for(i=0;i<n-1;++i){
        for(j=0;j<n-1-i;++j)
        if(x[j].vip<x[j+1].vip){
            temp=x[j];
            x[j]=x[j+1];
            x[j+1]=temp;
        }
        else if(x[j].vip==x[j+1].vip&&strcmp(x[j].name,x[j+1].name)>0){
            temp=x[j];
            x[j]=x[j+1];
            x[j+1]=temp;
        }
    }
    output(x,n);
}

void output(Contact x[], int n) {
    int i;

    for(i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if(x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}

 

posted @ 2024-12-22 21:07  朱宁苇  阅读(7)  评论(0编辑  收藏  举报