js 加减乘除工具类

let Float_Dolphin = function () {

/*
* 判断obj是否为一个整数
*/
function isInteger(obj) {
return Math.floor(obj) === obj
}

/*
* 将一个浮点数转成整数,返回整数和倍数。如 3.14 >> 314,倍数是 100
* @param floatNum {number} 小数
* @return {object}
* {times:100, num: 314}
*/
function toInteger(floatNum) {
let ret = {times: 1, num: 0};
if (isInteger(floatNum)) {
ret.num = floatNum;
return ret
}
let strfi = floatNum + '';
let dotPos = strfi.indexOf('.');
let len = strfi.substr(dotPos + 1).length;
let times = Math.pow(10, len);
let intNum = parseInt(floatNum * times + 0.5, 10);
ret.times = times;
ret.num = intNum;
return ret
}

/*
* 核心方法,实现加减乘除运算,确保不丢失精度
* 思路:把小数放大为整数(乘),进行算术运算,再缩小为小数(除)
*
* @param a {number} 运算数1
* @param b {number} 运算数2
* @param op {string} 运算类型,有加减乘除(add/subtract/multiply/divide)
*
*/
function operation(a, b, op) {
let o1 = toInteger(a);
let o2 = toInteger(b);
let n1 = o1.num;
let n2 = o2.num;
let t1 = o1.times;
let t2 = o2.times;
let max = t1 > t2 ? t1 : t2;
let result = null;
switch (op) {
case 'add':
if (t1 === t2) { // 两个小数位数相同
result = n1 + n2
} else if (t1 > t2) { // o1 小数位 大于 o2
result = n1 + n2 * (t1 / t2)
} else { // o1 小数位 小于 o2
result = n1 * (t2 / t1) + n2
}
return result / max;
case 'subtract':
if (t1 === t2) {
result = n1 - n2
} else if (t1 > t2) {
result = n1 - n2 * (t1 / t2)
} else {
result = n1 * (t2 / t1) - n2
}
return result / max;
case 'multiply':
result = (n1 * n2) / (t1 * t2);
return result;
case 'divide':
result = (n1 / n2) * (t2 / t1);
return result
}
}

// 加减乘除的四个接口
function add(a, b) {//加
return operation(a, b, 'add')
}

function subtract(a, b) {//减
return operation(a, b, 'subtract')
}

function multiply(a, b) {//乘
return operation(a, b, 'multiply')
}

function divide(a, b) {//除
return operation(a, b, 'divide')
}

// exports
return {
add: add,
subtract: subtract,
multiply: multiply,
divide: divide
}
}();

/**
* 使用例子
console.log(Float_Dolphin.add(0.1, 0.2));//0.3
console.log(Float_Dolphin.subtract(1.0, 0.9));//0.1
console.log(Float_Dolphin.multiply(19.9, 100));//1990
console.log(Float_Dolphin.divide(6.6, 0.2));//33
*/
posted @ 2020-11-10 10:12  卟萌  阅读(758)  评论(0编辑  收藏  举报