摘要: select years,months,abs( trunc( newer_date- add_months( older_date,years*12+months ) ) ) days from (select trunc(months_between( to_date('20180625', ' 阅读全文
posted @ 2018-07-25 11:51 zmztyas 阅读(3679) 评论(0) 推荐(0) 编辑