shell 加法

i=$i+1

是在i的变量值后加上字符串'+1'

 

 

总结:其他语言中的$i++操作在shell中表示如下:
#!/bin/bash

n=1;echo -n "$n "

let "n = $n + 1"
echo -n "$n "

: $((n = $n + 1))
echo -n "$n "

(( n = n +1 ))
echo -n "$n "

: $[ n = $n +1 ]
echo -n "$n "

n=$[ $n + 1 ]
echo -n "$n "

let "n++"
echo -n "$n "

(( n++ ))
echo -n "$n "

: $[ n++ ]
echo -n "$n "

echo

运行结果:1 2 3 4 5 6 7 8 9

 posted on 2014-06-05 16:29  zmlctt  阅读(2067)  评论(0编辑  收藏  举报