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2359: 巴什博弈？ 题目描述 有n个石子，有两人轮流从中取石子，最少a个最多b个，谁没得取（即当轮到他取是已经没有石子可以取了,也就是说此时石子数量小于a）谁赢，现在，LLM先取，问你LLM能赢吗 有n个石子，有两人轮流从中取石子，最少a个最多b个，谁没得取（即当轮到他取是已经没有石子可以取了, 阅读全文
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Freddy Frog is sitting on a stone in the middle of a lake. Suddenly he notices Fiona Frog who is sitting on another stone. He plans to visit her, but 阅读全文
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Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whe 阅读全文
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Given a connected undirected graph, tell if its minimum spanning tree is unique. Definition 1 (Spanning Tree): Consider a connected, undirected graph 阅读全文
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证明详细的博客：http://blog.csdn.net/hillgong/article/details/4214327 模板： 1 #include<iostream> 2 #include<algorithm> 3 #include<queue> 4 #include<cstdio> 5 #i 阅读全文
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The aspiring Roy the Robber has seen a lot of American movies, and knows that the bad guys usually gets caught in the end, often because they become t 阅读全文
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A group of researchers are designing an experiment to test the IQ of a monkey. They will hang a banana at the roof of a building, and at the mean time 阅读全文
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Jesus, what a great movie! Thousands of people are rushing to the cinema. However, this is really a tuff time for Joe who sells the film tickets. He i 阅读全文
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Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now y 阅读全文
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#include #define inf 1q; bool vis[100000]; memset(vis,0,sizeof vis); vis[s]=1; dis[s]=0; q.push(s); while(!q.empty()){ int f=q.front(); q.pop(); vis[f]... 阅读全文