实验六

task4.

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}
void output(Book x[], int n)
{    
    int i; 
    printf("ISBN号             书名             作者             售价     销售册数\n");
    for (i = 0; i < n; i++)
    {
        printf("%-15s    %-25s    %-20s    %-5g    %-5d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
    }
}
void sort(Book x[], int n)
{    
    int i,j;
    for ( i = 0; i < n - 1; i++)
    {
        for (j = 0; j < n-1-i; j++)
        {
            if (x[j].sales_count < x[j+1].sales_count)
            {
                Book temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
}
double sales_amount(Book x[], int n)
{
    double sum = 0;
    int i;
    for ( i = 0; i < n; i++)
    {
        sum += x[i].sales_price * x[i].sales_count;
    }
    return sum;
}

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}
void output(Book x[], int n)
{    
    int i; 
    printf("ISBN号             书名             作者             售价     销售册数\n");
    for (i = 0; i < n; i++)
    {
        printf("%-15s    %-25s    %-20s    %-5g    %-5d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
    }
}
void sort(Book x[], int n)
{    
    int i,j;
    for ( i = 0; i < n - 1; i++)
    {
        for (j = 0; j < n-1-i; j++)
        {
            if (x[j].sales_count < x[j+1].sales_count)
            {
                Book temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
}
double sales_amount(Book x[], int n)
{
    double sum = 0;
    int i;
    for ( i = 0; i < n; i++)
    {
        sum += x[i].sales_price * x[i].sales_count;
    }
    return sum;
}

 

task5.

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

// 函数声明
void input(Date *pd);                   // 输入日期给pd指向的Date变量
int day_of_year(Date d);                // 返回日期d是这一年的第多少天
int compare_dates(Date d1, Date d2);    // 比较两个日期: 
                                        // 如果d1在d2之前，返回-1;
                                        // 如果d1在d2之后，返回1
                                        // 如果d1和d2相同，返回0

void test1() {
    Date d;
    int i;

    printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);
        
        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

void input(Date *pd) 
{
    scanf("%d-%d-%d",&(*pd).year,&(*pd).month,&(*pd).day);
}
int day_of_year(Date d) 
{
    int days=0,i;
    int days_month[]={31,28,31,30,31,30,31,31,30,31,30,31};
    if(d.year%4==0&&d.year%100!=0||d.year%400==0)
        days_month[1]+=1;
    for(i=0;i<d.month-1;++i)
        days+=days_month[i];
    days+=d.day; 
    
    return days;
}

int compare_dates(Date d1, Date d2) 
{
    if(d1.year<d2.year)
        return -1;
    else if(d1.year>d2.year)
        return 1;
    else
    {
        if(d1.month<d2.month)
            return -1;
        else if(d1.month>d2.month)
            return 1;
        else
        {
            if(d1.day<d2.day)
                return -1;
            else if(d1.day>d2.day)
                return 1;
            else 
                return 0;
        }
    }
    
}

task6.

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};

typedef struct {
    char username[20];  // 用户名
    char password[20];  // 密码
    enum Role type;     // 账户类型
} Account;


// 函数声明
void output(Account x[], int n);    // 输出账户数组x中n个账户信息，其中，密码用*替代显示

int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student}, 
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);

    return 0;
}
void output(Account x[], int n) 
{
    int i,j,sum;
    char word[20];
    
    for(i=0;i<n;++i)
    {
        printf("%s\t",x[i].username);
        sum=strlen(x[i].password);
        for(j=0;j<sum;++j)
            word[j]='*';
        word[j]='\0';
        printf("%-20s",word);
        switch(x[i].type)
        {
            case 0:printf("admin\n");break;
            case 1:printf("student\n");break;
            case 2:printf("teacher\n");break;
            default:printf("somethint must be wrong");break;
        }
    }
         
}

task7.

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];     
    char phone[12];     
    int  vip;           
} Contact; 

void set_vip_contact(Contact x[], int n, char name[]);  
void output(Contact x[], int n);  
void display(Contact x[], int n);  


#define N 10
int main() {
    Contact list[N] = {{"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0}};
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n"); 
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    int i;
   for(i=0;i<n;i++){
       if(strcmp(x[i].name,name)==0){
           x[i].vip=1;
       }
   }
}

void display(Contact x[], int n) {
    Contact temp;
    int i,j;
    for(i=0;i<n-1;i++){
        for(j=0;j<n-i-1;j++){
             if (x[j].vip < x[j + 1].vip) {
                temp = x[j];
                x[j] = x[j + 1];
                x[j + 1] = temp;
            } else if (x[j].vip == x[j + 1].vip && strcmp(x[j].name, x[j + 1].name) > 0) {
                temp = x[j];
                x[j] = x[j + 1];
                x[j + 1] = temp;
            }
        }
    }
    output(x,n);
}

void output(Contact x[], int n) {
    int i;

    for(i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if(x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}