实验3
任务1
代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 #include <windows.h> 5 #define N 80 6 void print_text(int line, int col, char text[]); 7 void print_spaces(int n); 8 void print_blank_lines(int n); 9 int main() { 10 int line, col, i; 11 char text[N] = "hi, November~"; 12 srand(time(0)); 13 for(i = 1; i <= 10; ++i) { 14 line = rand() % 25; 15 col = rand() % 80; 16 print_text(line, col, text); 17 Sleep(1000); 18 } 19 return 0; 20 } 21 22 void print_spaces(int n) { 23 int i; 24 for(i = 1; i <= n; ++i) 25 printf(" "); 26 } 27 28 void print_blank_lines(int n) { 29 int i; 30 for(i = 1; i <= n; ++i) 31 printf("\n"); 32 } 33 34 void print_text(int line, int col, char text[]) { 35 print_blank_lines(line-1); 36 print_spaces(col-1); 37 printf("%s", text); 38 }
运行结果
代码作用：随机在屏幕上的某个位置输出 hi，+当前月份November，生成十个，每隔1秒生成一个
任务2
2.1
代码
1 #include <stdio.h> 2 long long fac(int n); // 函数声明 3 4 int main() { 5 int i, n; 6 7 printf("Enter n: "); 8 scanf("%d", &n); 9 10 for (i = 1; i <= n; ++i) 11 printf("%d! = %lld\n", i, fac(i)); 12 13 return 0; 14 } 15 16 // 函数定义 17 long long fac(int n) { 18 static long long p = 1; 19 printf("p = %lld\n", p); 20 p = p * n; 21 22 return p; 23 }
运行结果
2.2
代码
1 #include <stdio.h> 2 int func(int, int); 3 4 int main() { 5 int k = 4, m = 1, p1, p2; 6 7 p1 = func(k, m); 8 p2 = func(k, m); 9 printf("%d, %d\n", p1, p2); 10 11 return 0; 12 } 13 14 int func(int a, int b) { 15 static int m = 0, i = 2; 16 17 i += m + 1; 18 m = i + a + b; 19 20 return m; 21 }
运行结果
static变量作用：使得i与m的值仅被赋值一次，保留其运算后的值再进行下一次运算
任务3
代码
1 #include <stdio.h> 2 long long func(int n); 3 int main() { 4 int n; 5 long long f; 6 while (scanf("%d", &n) != EOF) { 7 f = func(n); 8 printf("n = %d, f = %lld\n", n, f); 9 } 10 return 0; 11 } 12 13 long long func(int n) { 14 if (n == 0) { 15 return 0; 16 } else 17 { 18 return 2 * func(n - 1) + 1; 19 } 20 }
运行截图
任务4
实现方式1
代码
1 #include <stdio.h> 2 int func(int n, int m); 3 4 int main() { 5 int n, m; 6 7 while(scanf("%d%d", &n, &m) != EOF) 8 printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m)); 9 10 return 0; 11 } 12 13 int func(int n,int m) 14 { 15 int ret = 1; 16 int i; 17 for (i = 1; i <= n; i++) 18 ret = ret * (m - i + 1) / i; 19 return ret; 20 }
截图
实现方式2
代码
1 #include <stdlib.h> 2 #include <stdio.h> 3 4 int func(int n, int m); 5 6 int main() 7 { 8 int n, m; 9 while(scanf("%d%d",&n,&m) != EOF) 10 printf("n = %d, m = %d, ans = %d\n", n, m, func(n,m)); 11 12 13 return 0; 14 } 15 16 int func(int n, int m) 17 { 18 int ans, ans1; 19 if(n < m) 20 { 21 ans1 = 0; 22 } 23 else if ( m == 1) 24 { 25 ans1 = n; 26 } 27 else if( m == 0) 28 { 29 ans1 = 1; 30 } 31 else 32 { 33 ans1 = func(n-1, m)+func(n-1, m-1); 34 } 35 36 return ans1; 37 }
结果
任务5
代码
1 #include<stdio.h> 2 int i = 0; 3 void hanoi(int n, char from, char temp, char to); 4 void moveplate(int n, char from, char to); 5 int main() 6 { 7 unsigned int n; 8 while (scanf("%u", &n) != EOF) 9 { 10 i = 0; 11 hanoi(n, 'A', 'B', 'C'); 12 printf("共移动了%d次\n", i); 13 14 } 15 return 0; 16 } 17 void hanoi(int n, char from, char temp, char to) 18 { 19 20 if (n == 1) 21 moveplate(n, from, to); 22 else 23 { 24 hanoi(n - 1, from, to, temp); 25 moveplate(n, from, to); 26 hanoi(n - 1, temp, from, to); 27 } 28 29 } 30 void moveplate(int n, char from, char to) 31 { 32 i++; 33 printf("%u:%c-->%c\n", n, from, to); 34 }
结果
任务6
代码
1 #include <stdio.h> 2 #include <math.h> 3 long func(long s); // 函数声明 4 int main() { 5 long s, t; 6 printf("Enter a number: "); 7 8 while (scanf("%ld", &s) != EOF) { 9 t = func(s); 10 printf("new number is: %ld\n\n", t); 11 printf("Enter a number: "); 12 } 13 return 0; 14 } 15 16 long func(long s) { 17 long n = 0; 18 long p = 1; 19 20 while (s > 0) { 21 long d = s % 10; 22 if (d % 2 == 1) { 23 n += d * p; 24 p *= 10; 25 } 26 s /= 10; 27 } 28 29 return n; 30 }
运行截图
