摘要: 1. let [ foo , [ [ bar ] , baz ] ]=[ 1 , [ [2] , 3] ]; foo //1 bar //2 baz //3 let [ , ,third]=["a","b","c"]; third //c let [x, ,y]=[1,2,3]; x //1; y 阅读全文
posted @ 2018-03-13 17:14 不积硅步无以至千里 阅读(927) 评论(0) 推荐(0) 编辑