实验六
任务4：
#include <stdio.h> #define N 10 typedef struct { char isbn[20]; char name[80]; char author[80]; double sales_price; int sales_count; } Book; void output(Book x[], int n); void sort(Book x[], int n); double sales_amount(Book x[], int n); int main() { Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; printf("图书销量排名(按销售册数): \n"); sort(x, N); output(x, N); printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); return 0; } void output(Book x[], int n){ int i; printf("isbn号 书名 作者 售价 销售册数\n") ; for (i = 0; i < n; i++) { printf("%-20s %-34s %-28s %-16.2f %d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count); } } void sort(Book x[], int n){ int i,j; Book t; for(i=0;i<n-1;i++){ for(j=0;j<n-1-i;j++){ if(x[j].sales_count < x[j+1].sales_count){ t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } } double sales_amount(Book x[], int n){ double sum=0; int i; for(i=0;i<n;i++){ sum+=x[i].sales_price * x[i].sales_count; } return sum; }
任务5：
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date *pd); int day_of_year(Date d); int compare_dates(Date d1, Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&d); printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); } } void test2() { Date Alice_birth, Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&Alice_birth); input(&Bob_birth); ans = compare_dates(Alice_birth, Bob_birth); if(ans == 0) printf("Alice和Bob一样大\n\n"); else if(ans == -1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main() { printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date *pd) { scanf("%d-%d-%d", &(pd->year), &(pd->month), &(pd->day)); } int day_of_year(Date d) { int day=0,i; int a[12]={31,28,31,30,31,30,31,31,30,31,30,31}; if ((d.year % 4 == 0 && d.year % 100!= 0) || d.year % 400 == 0) { a[1] = 29; }else{ a[1] = 28; } for(i=0;i<d.month-1;i++){ day+=a[i]; } day+=d.day; return day; } int compare_dates(Date d1, Date d2) { if (d1.year < d2.year) { return -1; } else if (d1.year > d2.year) { return 1; } else { if (d1.month < d2.month) { return -1; } else if (d1.month > d2.month) { return 1; } else { if (d1.day < d2.day) { return -1; } else if (d1.day > d2.day) { return 1; } else { return 0; } } } }
任务6：
#include <stdio.h> #include <string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main() { Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { int i,j; char m='*'; char a[7]="admin",s[7]="student",t[7]="teacher"; for (i = 0; i < n; i++) { printf("%-10s", x[i].username); int passwordLength = strlen(x[i].password); for (j = 0; j < passwordLength-1; j++) { printf("*"); } printf("%-10c",m); switch (x[i].type) { case admin: printf("%-10s\n",a); break; case student: printf("%-10s\n",s); break; case teacher: printf("%-10s\n",t); break; default: break; } } }
任务7：
#include <stdio.h> #include <string.h> typedef struct { char name[20]; char phone[12]; int vip; } Contact; void set_vip_contact(Contact x[], int n, char name[]); void output(Contact x[], int n); void display(Contact x[], int n); #define N 10 int main() { Contact list[N] = {{"刘一", "15510846604", 0}, {"陈二", "18038747351", 0}, {"张三", "18853253914", 0}, {"李四", "13230584477", 0}, {"王五", "15547571923", 0}, {"赵六", "18856659351", 0}, {"周七", "17705843215", 0}, {"孙八", "15552933732", 0}, {"吴九", "18077702405", 0}, {"郑十", "18820725036", 0}}; int vip_cnt, i; char name[20]; printf("显示原始通讯录信息: \n"); output(list, N); printf("\n输入要设置的紧急联系人个数: "); scanf("%d", &vip_cnt); printf("输入%d个紧急联系人姓名:\n", vip_cnt); for(i = 0; i < vip_cnt; ++i) { scanf("%s", name); set_vip_contact(list, N, name); } printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); display(list, N); return 0; } void set_vip_contact(Contact x[], int n, char name[]) { int i; for(i=0;i<n;i++){ if(strcmp(x[i].name,name)==0){ x[i].vip=1; } } } void display(Contact x[], int n) { Contact temp; int i,j; for(i=0;i<n-1;i++){ for(j=0;j<n-i-1;j++){ if (x[j].vip < x[j + 1].vip) { temp = x[j]; x[j] = x[j + 1]; x[j + 1] = temp; } else if (x[j].vip == x[j + 1].vip && strcmp(x[j].name, x[j + 1].name) > 0) { temp = x[j]; x[j] = x[j + 1]; x[j + 1] = temp; } } } output(x,n); } void output(Contact x[], int n) { int i; for(i = 0; i < n; ++i) { printf("%-10s%-15s", x[i].name, x[i].phone); if(x[i].vip) printf("%5s", "*"); printf("\n"); } }
