HDU 2212 DFS

http://acm.hdu.edu.cn/showproblem.php?pid=2212

 

Problem Description

A DFS(digital factorial sum) number is found by summing the factorial of every digit of a positive integer. 

For example ,consider the positive integer 145 = 1!+4!+5!, so it's a DFS number.

Now you should find out all the DFS numbers in the range of int( [1, 2147483647] ).

There is no input for this problem. Output all the DFS numbers in increasing order. The first 2 lines of the output are shown below.

 

Input

no input

 

Output

Output all the DFS number in increasing order.

 

Sample Output

1 2 ......

代码：

#include <bits/stdc++.h>
using namespace std;

int main() {
    printf("1\n2\n145\n40585\n");
    return 0;
}