#Leetcode# 707. Design Linked List
https://leetcode.com/problems/design-linked-list/
Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes: val
and next
. val
is the value of the current node, and next
is a pointer/reference to the next node. If you want to use the doubly linked list, you will need one more attribute prev
to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement these functions in your linked list class:
- get(index) : Get the value of the
index
-th node in the linked list. If the index is invalid, return-1
. - addAtHead(val) : Add a node of value
val
before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. - addAtTail(val) : Append a node of value
val
to the last element of the linked list. - addAtIndex(index, val) : Add a node of value
val
before theindex
-th node in the linked list. Ifindex
equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. - deleteAtIndex(index) : Delete the
index
-th node in the linked list, if the index is valid.
Example:
MyLinkedList linkedList = new MyLinkedList(); linkedList.addAtHead(1); linkedList.addAtTail(3); linkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 linkedList.get(1); // returns 2 linkedList.deleteAtIndex(1); // now the linked list is 1->3 linkedList.get(1); // returns 3
Note:
- All values will be in the range of
[1, 1000]
. - The number of operations will be in the range of
[1, 1000]
. - Please do not use the built-in LinkedList library.
代码:
class MyLinkedList { public: /** Initialize your data structure here. */ MyLinkedList() { head = NULL; sz = 0; } /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */ int get(int index) { if(index < 0 || index >= sz) return -1; ListNode *cur = head; for(int i = 0; i < index; i ++) cur = cur -> next; return cur -> val; } /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */ void addAtHead(int val) { ListNode *pre = new ListNode(val, head); head = pre; sz ++; } /** Append a node of value val to the last element of the linked list. */ void addAtTail(int val) { ListNode *pre = head; while(pre -> next) pre = pre -> next; pre -> next = new ListNode(val, NULL); sz ++; } /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */ void addAtIndex(int index, int val) { if(index < 0 || index > sz) return; if(index == 0) { addAtHead(val); return; } ListNode *pre = head; for(int i = 0; i < index - 1; i ++) pre = pre -> next; ListNode *cur = new ListNode(val, pre -> next); pre -> next = cur; sz ++; } /** Delete the index-th node in the linked list, if the index is valid. */ void deleteAtIndex(int index) { if(index < 0 || index >= sz) return; if(index == 0) { head = head -> next; sz --; return; } ListNode *pre = head; for(int i = 0; i <index - 1; i ++) pre = pre -> next; pre -> next = pre -> next -> next; sz --; } private: struct ListNode { int val; ListNode *next; ListNode(int x, ListNode *n): val(x),next(n) {} }; ListNode *head, *tail; int sz; }; /** * Your MyLinkedList object will be instantiated and called as such: * MyLinkedList obj = new MyLinkedList(); * int param_1 = obj.get(index); * obj.addAtHead(val); * obj.addAtTail(val); * obj.addAtIndex(index,val); * obj.deleteAtIndex(index); */
这个写完之后仿佛已经搞清楚了链表 但愿不是错觉叭