摘要: /********一维差值函数*******/ double inter_linear(double x0, double x1, double y0, double y1, double x){ double a0, a1, y; a0 = (x - x1) / (x0 - x1); a1 = ( 阅读全文
posted @ 2020-03-04 21:39 zhoulei888 阅读(1113) 评论(0) 推荐(0) 编辑