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摘要: Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical a 阅读全文
posted @ 2017-10-26 10:15 乐乐章 阅读(135) 评论(0) 推荐(0) 编辑
摘要: labuladong 题解思路 难度中等 899 给出二叉 搜索 树的根节点,该树的节点值各不相同,请你将其转换为累加树(Greater Sum Tree),使每个节点 node 的新值等于原树中大于或等于 node.val 的值之和。 提醒一下,二叉搜索树满足下列约束条件: 节点的左子树仅包含键  阅读全文
posted @ 2017-10-26 10:04 乐乐章 阅读(137) 评论(0) 推荐(0) 编辑
摘要: You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contai 阅读全文
posted @ 2017-10-26 08:59 乐乐章 阅读(117) 评论(0) 推荐(0) 编辑
摘要: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given 1->2 阅读全文
posted @ 2017-10-25 10:06 乐乐章 阅读(197) 评论(0) 推荐(0) 编辑
摘要: Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the 阅读全文
posted @ 2017-10-25 09:36 乐乐章 阅读(142) 评论(0) 推荐(0) 编辑
摘要: Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the 阅读全文
posted @ 2017-10-24 22:29 乐乐章 阅读(101) 评论(0) 推荐(0) 编辑
摘要: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After rem 阅读全文
posted @ 2017-10-23 20:19 乐乐章 阅读(141) 评论(0) 推荐(0) 编辑
摘要: Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your a 阅读全文
posted @ 2017-10-22 20:48 乐乐章 阅读(109) 评论(0) 推荐(0) 编辑
摘要: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contai 阅读全文
posted @ 2017-10-21 22:31 乐乐章 阅读(185) 评论(0) 推荐(0) 编辑
摘要: Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2- 阅读全文
posted @ 2017-10-20 22:11 乐乐章 阅读(197) 评论(0) 推荐(0) 编辑
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