9. Palindrome Number(判断整型数字是否是回文，直接暴力即可)

Determine whether an integer is a palindrome. Do this without extra space.

 

 

class Solution:
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        x =str(x)


        for i in range(int(len(x)/2)+1):
            if(x[i]!=x[len(x)-i-1]):
                return False
    
        return True