/*
* @lc app=leetcode.cn id=105 lang=java
*
* [105] 从前序与中序遍历序列构造二叉树
*/
// @lc code=start
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode buildTree(int[] preorder, int[] inorder) {
if(preorder== null || preorder.length <= 0){
return null;
}
int preL = 0, preR = preorder.length - 1;
int inL = 0, inR = inorder.length - 1;
return helper(preorder, preL, preR, inorder, inL, inR);
}
public TreeNode helper(int[] preorder, int preL, int preR, int[] inorder, int inL, int inR){
if(preL > preR || inL > inR || preR > preorder.length || inR > inorder.length){
return null;
}
int rootIndex = 0;
TreeNode root = new TreeNode(preorder[preL]);
for(int i = inL; i <= inR; i++){
if(inorder[i] == root.val){
rootIndex = i;
break;
}
}
root.left = helper(preorder, preL + 1, preL + (rootIndex - inL), inorder, inL, rootIndex - 1);
root.right = helper(preorder, preL + (rootIndex - inL) + 1, preR, inorder, rootIndex + 1, inR);
return root;
}
}
// @lc code=end