最小最大堆

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//最小最大堆的定义,一颗完全二叉树,根节点为最小层,最小层和最大层交替出现,如果x为最小层的节点,那么他就是以x为根节点的二叉树

的最小节点,如果x为最大层的节点,那么他就是以x为根节点的二叉树的最大节点

//支持双端队列的实现(1:能够插入任意一个值 2:能够删除最大值 3:能够删除最小值)

//实现从节点1开始,0舍弃

/*

* 2009/06/03 By xylh

* */

#include <stdio.h>

#include <stdlib.h>

#define MAXSIZE 1000

struct element {

        int key;

};

element heap[MAXSIZE];

//判断节点所在是最大还是最小层,最小层返回true

bool level(int i)

{

    double k = log(i)/log(2);

    if((int)k%2 ==0) return true;

    else return false;

}

//在最大层向上追溯

void max_verify(element heap[], int n, element item)

{

        int i = n;

        int parent = n/4;

        while(parent) {

                if(heap[parent].key < item.key) {

                        heap[i] = heap[parent];

                        i = parent;

                        parent = parent/4;

                } else {

                        break;

                }

        }

        heap[i] = item;

}

void min_verify(element heap[], int n, element item)

{

        int i = n;

        int parent = n/4;

        while(parent) {

                if(heap[parent].key > item.key) {

                        heap[i] = heap[parent];

                        i = parent;

                        parent = parent/4;

                } else {

                        break;

                }

        }

        heap[i] = item;

}

void insert(element heap[], int *n, element item)

{

        (*n)++;

        if(*n == MAXSIZE) {

                printf("heap is full\n");

                exit(1);

        }

        if(*n == 1) {

                heap[*n].key = item.key;

                return;

        }

        int parent = *n/2;

        switch(level(parent)) {

        case true:

                if(heap[parent].key > item.key) {

                        heap[*n] = heap[parent];

                        min_verify(heap, parent, item);

                } else {

                        max_verify(heap, *n, item);

                }

                break;

        case false:

                if(heap[parent].key < item.key) {

                        heap[*n] = heap[parent];

                        max_verify(heap, parent, item);

                } else {

                        min_verify(heap, *n, item);

                }

                break;

        }

}

//寻找子节点和后序节点中最小的节点

int min_grand_child(element heap[], int n, int i)

{

        int min = 2*i;

        int k[5] = {2*i+1, 4*i, 4*i+1, 4*i+2, 4*i+3};

        for(int j=0; k[j]<=n&&j<=4; ++j) {

                if(heap[k[j]].key < heap[min].key)

                        min = k[j];

        }

        return min;

}

element del_min(element heap[], int *n)

{

        if(*n < 1) {

                printf("heap is empty\n");

                exit(1);

        }

        if(*n == 1) return heap[(*n)--];//case 1

        element item = heap[(*n)--];

        heap[0].key = heap[1].key;

        int k, i, last = (*n)/2, parent;

        for(i=1; i<=last; ) {

                k = min_grand_child(heap, *n, i);

                if(item.key <= heap[k].key) break;//case 2(a)

                heap[i] = heap[k];

                if(k <= 2*i+1) {//case 2(b)

                        i = k;

                        break;

                }

                parent = k/2;//case 2(c)

                if(item.key > heap[parent].key) {

                        element temp = item;

                        item = heap[parent];

                        heap[parent] = temp;

                }

                i = k;

        }

        heap[i] = item;

        return heap[0];

}

element del_max(element heap[], int *n)

{

 

}

int main()

{

        int n = 0;

        for(int i=1; i<=10; ++i) {

                element item;

                item.key = i;

                insert(heap, &n, item);

        }

        del_min(heap, &n);

        for(int i=1; i<=n; ++i) {

                printf("%d ", heap[i].key);

        }

        printf("\n");

        return 0;

}

 

 

 

struct heap{
    int size;
    int a[11000];
    heap(){size=0;}
    void insert(int x){
         int p;
         for(p=++size;p>1&&a[p>>1]>x;a[p]=a[p>>1],p>>=1);
         a[p]=x;
         }
    void pop(int &x){
         int p,c;
         for(x=a[p=1],c=2;c<size&&(a[c+=(c+1<size&&a[c+1]<a[c])?1:0]<a[size]);a[p]=a[c],p=c,c<<=1);
         a[p]=a[size--];
         }
    }h;

posted @ 2013-05-24 13:24  紫long  阅读(488)  评论(0编辑  收藏  举报