Safari 里的javascript 里不能用submit作为函数名

Safari 里的javascript 里不能用submit作为函数名, 这样写的时候,怎么也运行不了JeasyUI的onSubmit的function, 改个名就可以了.而在chrome下面就没问题

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function submit() {       $('#form').form('submit', {         onSubmit: function () {             var account = $("#txtLoginId").val();             var password = $("#txtPwd").val();             var code = $("#txtCode").val();               if (account == "" || password == "" || code == "") {                 alert("请输入用户名，密码和验证码");                 return false;             }               return $(this).form('validate');         },         success: function (json) {                           var json = eval('(' + json + ')');  // change the JSON string to javascript object             if (json.isSuccess)                     window.top.location.href = "/?culture="+ $("#ddlLang").val();             else                 alert(json.message);                       }     }); }