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问题描述：Given a roman numeral, convert it to an integer.Input is guaranteed to be within the range from 1 to 3999.解题思路：上一题反过来就可以了，其实觉得这两道题很没有意思。代码如下：publ... 阅读全文
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题目描述：Given an integer, convert it to a roman numeral.Input is guaranteed to be within the range from 1 to 3999.解题思路：这道题没什么技术含量，一个一个除10以及取模运算就行。代码如下：pu... 阅读全文
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问题描述：Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two ... 阅读全文
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问题描述：Implement regular expression matching with support for '.' and '*'.'.' Matches any single character.'*' Matches zero or more of the preceding ele... 阅读全文
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问题描述：Determine whether an integer is a palindrome. Do this without extra space.Some hints:Could negative integers be palindromes? (ie, -1)If you are t... 阅读全文
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问题描述：Implement atoi to convert a string to an integer.Hint: Carefully consider all possible input cases. If you want a challenge, please do not see be... 阅读全文
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问题描述：Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321Have you thought about this?Here are some good question... 阅读全文
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问题描述：The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed ... 阅读全文
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问题描述：Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique l... 阅读全文
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问题描述：There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexi... 阅读全文
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问题描述：Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating lette... 阅读全文
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问题描述：You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a si... 阅读全文
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小二终于开通博客了，真是高兴。最近在看Java，所以就拿leetcode练练手了。以后我会将自己解体过程中的思路写下来，分享给大家，其中有我自己原创的部分，也有参考别人的代码加入自己理解的部分，希望大家看了多提意见，一块加油。问题描述：Given an array of integers, find... 阅读全文