Spring Security Form Login
原文地址：http://www.javaarch.net/jiagoushi/695.htm
Spring Security Form Login
web.xml配置
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xsi:schemaLocation="
http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>Spring Secured Application</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>org.baeldung.spring.web.config</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
Spring Security configuration
@Configuration
@ImportResource({ "classpath:webSecurityConfig.xml" })
public class SecSecurityConfig {
public SecSecurityConfig() {
super();
}
}
webSecurityConfig.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xsi:schemaLocation="
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd">
<http use-expressions="true">
<intercept-url pattern="/login*" access="isAnonymous()" />
<intercept-url pattern="/**" access="isAuthenticated()"/>
<form-login
login-page='/login.html'
default-target-url="/homepage.html"
authentication-failure-url="/login.html?error=true" />
<logout logout-success-url="/login.html" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="user1" password="user1Pass" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
登录表单Login Form，注册登录url，
registry.addViewController("/login.html");
登录首页login.jsp
<html>
<head></head>
<body>
<h1>Login</h1>
<form name='f' action="j_spring_security_check" method='POST'>
<table>
<tr>
<td>User:</td>
<td><input type='text' name='j_username' value=''></td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='j_password' /></td>
</tr>
<tr>
<td><input name="submit" type="submit" value="submit" /></td>
</tr>
</table>
</form>
</body>
</html>
<form-login>配置可以支持更多
<form-login
login-page='/login.html'
login-processing-url="/perform_login"
default-target-url="/homepage.html"
authentication-failure-url="/login.html?error=true"
always-use-default-target="true"/>
示例工程在https://github.com/eugenp/tutorials/tree/master/spring-security-login#readme，可以访问http://localhost:8080/spring-security-login/login.html进入登录首页进行登录。
