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树的子结构

public class Solution {
  
public boolean HasSubtree(TreeNode root1,TreeNode root2) {   boolean ret = false;   if(root1 == null || root2 == null) return ret;   ret = helper(root1,root2);   if(!ret) ret = helper(root1.left,root2);   if(!ret) ret = helper(root1.right,root2);   return ret;   }   public boolean helper(TreeNode root1, TreeNode root2) {   if(root2==null) return true;   if(root1==null) return false;   if(root1.val != root2.val) return false;   return helper(root1.left, root2.left) && helper(root1.right, root2.right);   } }

 

posted on 2019-02-28 13:58  www_practice  阅读(127)  评论(0编辑  收藏  举报