A1126. Eulerian Path

In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard Euler while solving the famous Seven Bridges of Konigsberg problem in 1736. It has been proven that connected graphs with all vertices of even degree have an Eulerian circuit, and such graphs are called Eulerian. If there are exactly two vertices of odd degree, all Eulerian paths start at one of them and end at the other. A graph that has an Eulerian path but not an Eulerian circuit is called semi-Eulerian. (Cited from https://en.wikipedia.org/wiki/Eulerian_path)

Given an undirected graph, you are supposed to tell if it is Eulerian, semi-Eulerian, or non-Eulerian.

Input Specification:

Each input file contains one test case. Each case starts with a line containing 2 numbers N (<= 500), and M, which are the total number of vertices, and the number of edges, respectively. Then M lines follow, each describes an edge by giving the two ends of the edge (the vertices are numbered from 1 to N).

Output Specification:

For each test case, first print in a line the degrees of the vertices in ascending order of their indices. Then in the next line print your conclusion about the graph -- either "Eulerian", "Semi-Eulerian", or "Non-Eulerian". Note that all the numbers in the first line must be separated by exactly 1 space, and there must be no extra space at the beginning or the end of the line.

Sample Input 1:

7 12
5 7
1 2
1 3
2 3
2 4
3 4
5 2
7 6
6 3
4 5
6 4
5 6

Sample Output 1:

2 4 4 4 4 4 2
Eulerian

Sample Input 2:

6 10
1 2
1 3
2 3
2 4
3 4
5 2
6 3
4 5
6 4
5 6

Sample Output 2:

2 4 4 4 3 3
Semi-Eulerian

Sample Input 3:

5 8
1 2
2 5
5 4
4 1
1 3
3 2
3 4
5 3

Sample Output 3:

3 3 4 3 3
Non-Eulerian

 1 #include<cstdio>
 2 #include<iostream>
 3 #include<algorithm>
 4 using namespace std;
 5 int G[501][501] = {0,0}, visit[501] = {0};
 6 int N, M;
 7 void DFS(int vt){
 8     visit[vt] = 1;
 9     for(int i = 1; i <= N; i++){
10         if(G[vt][i] != 0 && visit[i] == 0)
11             DFS(i);
12     }
13 }
14 int main(){
15     scanf("%d%d", &N, &M);
16     for(int i = 0; i < M; i++){
17         int v1, v2;
18         scanf("%d%d", &v1, &v2);
19         G[v1][v2] = G[v2][v1] = 1;
20     }
21     int odds = 1, even = 1, cnt = 0;
22     for(int i = 1; i <= N; i++){
23         int sum = 0;
24         for(int j = 1; j <= N; j++){
25             sum += G[i][j];
26         }
27         if(i == N)
28             printf("%d\n", sum);
29         else printf("%d ", sum);
30         if(sum % 2 == 0){
31             odds = 0;
32         }else{
33             even = 0;
34             cnt++;
35         }
36     }
37     DFS(1);
38     for(int i = 1; i <= N; i++)
39         if(visit[i] == 0){
40             printf("Non-Eulerian");
41             return 0;
42         }
43     if(even == 1){
44         printf("Eulerian");
45     }else if(cnt == 2){
46         printf("Semi-Eulerian");
47     }else printf("Non-Eulerian");
48     cin >> N;
49     return 0;
50 
51 }
View Code

总结：

1、容易被忽略的：Semi-Eulerian和 Eulerian都是建立在连通图的基础上。最开始忽略了连通图的条件，结果有一个测试点过不去。应该先判断是否连通，不连通为 Non-Eulerian。

posted @ 2018-03-04 17:47  ZHUQW  阅读(152)  评论(0)  编辑  收藏  举报