A1065. A+B and C (64bit)

Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

 1 #include<cstdio>
 2 #include<iostream>
 3 using namespace std;
 4 int main(){
 5     int T;
 6     long long a, b, c, test;
 7     scanf("%d", &T);
 8     for(int i = 0; i < T; i++){
 9         scanf("%lld%lld%lld", &a, &b, &c);
10         test = a + b;
11         if(a >0 && b > 0 && test < 0){
12             printf("Case #%d: true\n", i + 1);
13         }else if(a < 0 && b < 0 && test >= 0){
14             printf("Case #%d: false\n", i + 1);
15         }else{
16             if(test > c)
17                 printf("Case #%d: true\n", i + 1);
18             else
19                 printf("Case #%d: false\n", i + 1);
20         }
21     }
22     return 0;
23 }
View Code

总结：1、首先输入的范围在[-2^63, 2^63], 则只能用long long 8个byte存储。当a与b过大时，会产生溢出，需要考虑正数+正数=负数及负数+负数=正数的情况。

　　　2、A + B的结果不能在条件语句中直接与C比较，必须先存储于long long变量中。

posted @ 2018-01-17 11:24  ZHUQW  阅读(123)  评论(0)  编辑  收藏  举报