题目1042：Coincidence(最长公共子序列)

题目1042：Coincidence

时间限制：1 秒

内存限制：32 兆

特殊判题：否

提交：2939

解决：1591

题目描述：

Find a longest common subsequence of two strings.

输入：

First and second line of each input case contain two strings of lowercase character a…z. There are no spaces before, inside or after the strings. Lengths of strings do not exceed 100.

输出：

For each case, output k – the length of a longest common subsequence in one line.

样例输入：

abcd
cxbydz

样例输出：

2

#include<iostream>
#include<stdio.h>
#include<queue>
#include<string>
#include<string.h>
#include<algorithm>
using namespace std;


int dp[101][101];
int max(int a,int b)
{
    return a>b?a:b;
}
int main()
{
    char s1[101],s2[101];
    while(scanf("%s%s",s1,s2)!=EOF)
    {
        int l1=strlen(s1);
        int l2=strlen(s2);
        for(int i=0; i<=l1; i++)
            dp[i][0]=0;
        for(int j=0; j<=l2; j++)
            dp[0][j]=0;
        for(int i=1; i<=l1; i++)
            for(int j=1; j<=l2; j++)
            {
                if(s1[i-1]!=s2[j-1])
                {
                    dp[i][j]=max(dp[i][j-1],dp[i-1][j]);
                }
                else
                    dp[i][j]=dp[i-1][j-1]+1;
            }
            printf("%d\n",dp[l1][l2]);
    }
    return 0;
}