JAVA实现二分查找

                北京时间2022年03月13日,晚22:06分。天气晴朗,多云,温度28。今天来实现JAVA二分查找,二分查找的前提是数组有序,核心思想是比较target和array[mid]的关系,如果target大于array[mid]就到右边找,反之到左边找。实现方式有两种:递归实现以及迭代实现。

(一)、代码实现:

public static void main(String[] args){
int[] array = {0,1,2,3,4,5,6,7};
int[] arrays = {-99,-98,1,3,4,11,15,17};
int index = RecursiveFind(arrays,-111,0,7);
// int indexs = IteratorFind(arrays,-999);
System.out.println("index = "+index);
// System.out.println("indexs = "+indexs);
}
/**
* 递归实现
*/
public static int RecursiveFind(int[] array,int target,int start,int end){
int mid = (end+start)/2;
if (start>end || 0>end){
return -1;
}
if (target>array[mid]){
return RecursiveFind(array,target,mid+1,end);
}else if (target<array[mid]){
return RecursiveFind(array,target,start,mid-1);
}else if (target==array[mid]){
return mid;
}else {
return -1;
}
}
/**
* 迭代实现
*/
public static int IteratorFind(int[] array,int target){
int left = 0;
int right = array.length-1;
// 迭代实现使用while循环
while (left<=right){
int mid = (right+left)/2;
if (target>array[mid]){
left = mid+1;
}else if (target<array[mid]){
right = mid-1;
}else {
return mid;
}
}
return -1;
}
posted @ 2022-03-13 22:10  卓不庭  阅读(342)  评论(0编辑  收藏  举报