2014-05-06 07:56
原题:
Flatten an iterator of iterators in Java. If the input is [ [1,2], [3,[4,5]], 6], it should return [1,2,3,4,5,6]. Implement hasNext() and next(). Note that the inner iterator or list might be empty.
题目:给定一个动态类型的数组,把其中的数组全部展开,成为一个一维数组。
解法:严格类型语言显然不允许这种数据,所以我用Python写了一版代码。
代码:
1 # http://www.careercup.com/question?id=5898529851572224 2 #!/usr/bin/python 3 4 def flatten(container, new_container): 5 for element in container: 6 if isinstance(element, list) or isinstance(element, tuple) or isinstance(element, set): 7 flatten(element, new_container) 8 else: 9 new_container.append(element) 10 pass 11 12 if __name__ == '__main__': 13 a = [1, 2.3, [3, [1, 222]], (4, 111, 0), "string", set([1, "hello", 3.33])] 14 res = [] 15 flatten(a, res) 16 print(res) 17 pass 18