Remove Duplicates from Sorted List
2013.12.26 21:36
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
Solution:
Removing the duplicates from a list requires two pointers ptr1 and ptr2. With ptr1 pointing to current node, and ptr2 next to ptr1, the operation can be done in only one-pass. Please see the code below.
Time complexity is O(n), space complexity is O(1).
Accepted code:
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode *deleteDuplicates(ListNode *head) { 12 // Note: The Solution object is instantiated only once and is reused by each test case. 13 if(head == nullptr){ 14 return head; 15 } 16 17 ListNode *ptr1, *ptr2; 18 19 ptr1 = head; 20 ptr2 = head->next; 21 while(ptr2 != nullptr){ 22 if(ptr1->val == ptr2->val){ 23 ptr1->next = ptr2->next; 24 delete ptr2; 25 ptr2 = ptr1->next; 26 }else{ 27 ptr1 = ptr1->next; 28 ptr2 = ptr1->next; 29 } 30 } 31 32 return head; 33 } 34 };
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