摘要: --82 SELECT COUNT(*) FROM [tbiz_PuzzleBasic] SELECT A.BasicID,A.Name,A.Gender,B.WorkID,B.Company,B.Position FROM [tbiz_PuzzleBasic] A LEFT JOIN [tbiz_ 阅读全文
posted @ 2019-02-15 11:29 轴轴 阅读(524) 评论(0) 推荐(0) 编辑