ZJFC-1239
这是一道省赛题目 解法是构造概率矩阵A 根据要进行的次数n 使用二分法计算转移矩阵(A)^n 再使用转移公式res=init*(A)^n
可以很快计算出最终答案
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#include <iostream>
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using namespace std;
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double hash[30];
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double mm[30];
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double matrix[30][30];
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double temp[30][30];
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long N;
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void Mulity(double m1[][30] ,double m2[][30])
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{
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long i,j,k;
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double tt[30][30];
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memset(tt,0,sizeof(tt));
13![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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for (i=1;i<=N;++i)
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{
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for (j=1;j<=N;++j)
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{
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double t=0;
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for (k=1;k<=N;++k)
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{
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t+=m1[i][k]*m2[k][j];
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}
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tt[i][j]=t;
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}
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}
26![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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memcpy(m1,tt,sizeof(tt));
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};
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int main()
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{
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long T;
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scanf("%ld",&T);
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while (T--)
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{
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memset(matrix,0,sizeof(matrix));
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scanf("%ld",&N);
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long i,k;
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for (i=1;i<=N;++i)
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{
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scanf("%lf",&hash[i]);
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}
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for (i=1;i<=N;++i)
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{
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long t;
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scanf("%ld",&t);
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double rate=1.0/t;
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while (t--)
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{
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long other;
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scanf("%ld",&other);
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matrix[i][other]=rate;
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}
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}
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long n;
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scanf("%ld",&n);
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long p=n;
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memset(temp,0,sizeof(temp));
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for (i=1;i<30;++i)
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{
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temp[i][i]=1;
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}
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while (p>1)
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{
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if (p%2!=0)
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{
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Mulity(temp,matrix);
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}
78![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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Mulity(matrix,matrix);
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p/=2;
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}
82![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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Mulity(matrix,temp);
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memset(mm,0,sizeof(mm));
85![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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for (i=1;i<=N;++i)
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{
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double t=0;
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for (k=1;k<=N;++k)
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{
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t+=hash[k]*matrix[k][i];
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}
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mm[i]=t;
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}
95![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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memcpy(hash,mm,sizeof(mm));
97![](https://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif)
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for (i=1;i<=N;++i)
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{
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if (i!=1)
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{
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printf(" ");
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}
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printf("%.2lf",hash[i]);
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}
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printf("\n");
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}
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return 0;
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}
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