摘要: public boolean isCircle() { if(first == null || first.next == null) return false; Node<U> slow = first; Node<U> fast = first.next; int i = 1; while (f 阅读全文
posted @ 2021-09-18 17:20 小庄的blog 阅读(42) 评论(0) 推荐(0) 编辑